Yahoo Answers: Answers and Comments for Terminal speed of two raindrop [其他  科學]
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From 冠邦
zhHantHK
Thu, 14 Jun 2007 16:04:19 +0000
3
Yahoo Answers: Answers and Comments for Terminal speed of two raindrop [其他  科學]
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From tc: Yes, you are right. We can apply this formula...
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Mon, 18 Jun 2007 15:33:40 +0000
Yes, you are right. We can apply this formula:
D = 1/2 C ρ A v²
where D = drag force
C = drag coefficient
ρ = density
A = crosssectional area
v = speed
To find the terminal velocity, setting the drag force D equal to the gravity of the raindrop, i.e.
D = mg = ρ(4/3 π r³) g, where r is the radius of the raindrop
=> ρ(4/3 π r³) g = 1/2 C ρ π r² v²
=> v = √ [(8/3 r g ) / C]
Hence, v is proportional to the square root of the radius of the raindrop.
Therefore, the bigger raindrop has higher terminal speed.
Note: The drag coefficient, C, is only approximately constant for the raindrops of different sizes. The shape of the raindrops are only approximately spherical.

From 志仁: I do not understand your last sentence.
The f...
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Thu, 14 Jun 2007 16:25:53 +0000
I do not understand your last sentence.
The force addes on the raindrop is F=mgbv, m is the mass of the raindrop.
m=pV, V is the volume, p is density.b is the air resistance constant depend on the surface area. V=4/3(pi)r^3. (Volume of a sphere)
Asume the two raindrops are sphere in shape.
And the terminal speed, F=0. => mg=bv, b=2(pi)r^2 x c (Area of half of sphere), c is a constant.
v=mg/b=p 4/3(pi)r^3 / c [2(pi)r^2] = p/c x (2r/3)
v is proprotional to r, that mean if the r is double, the terminal speed is double.
20070614 16:27:12 補充：
Since p, c are the same for the same matter.