匿名
匿名 發問於 科學及數學物理學 · 4 月前

物理問題一條,麻煩大家幫幫手!><?

A 63 kg hiker is dangling over the edge of an icy cliff. His partner (80 kg) is standing on icy ground holding a rope to keep the dangling hiker from falling. What coefficient of friction is needed to keep them from sliding?

1 個解答

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  • Jenkin
    Lv 7
    4 月前
    最愛解答

    Assume non-elastic force transfers,

    63kg hiker hanging in air of the cliff = 63 x 9.81 = 618.03N

    To hold this pulling force, the partner standing on "ice" ground require a weight force resistance on the ground without sliding (no moving):

    Pulling Force P = Friction Force = u W = coefficient of friction (of ice surface against the foot of the person) x weight of the person.

    618.03 = u (80kgx9.81)

    u = 0.7875

    好似好簡單...! 

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