Fluid Mechanics

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Can you solve Q3(b)(i),(ii),(iii),(iv)?

1 個解答

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  • 天同
    Lv 7
    5 年 前
    最佳解答

    (i) Volume of box = (pi x 0.5^2) x 0.4 m^3 = 0.3142 m^3

    Weight of box = 0.3142 x 900g N = 2827 N

    [Take g, the acceleration due to gravity, to be 10 m/s^2]

    (ii) Upthrust = 2827 N

    Mass of water displaced = 2827/g kg = 282.7 kg

    Volume of water displaced = 282.7/1000 m^3 = 0.2827 m^3

    Hence, h = 0.2827/(pi x 0.5^2) m = 0.3599 m

    (iii) Pressure = 0.3599 x 1000g N/m^2 = 3599 N/m^2

    (iv) Upthrust when box is totally immersed

    = 0.3142 x 1000g N = 3142 N

    Hence, force required = (3142 - 2827) N = 315 N

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