Two blocks connected by a thread are being pulled horizontally by a force 40N as shown in. Assume no friction in between the floor and the blocks.
a)Find the tension T on the two blocks.
b)What is the acceleration of the 3 kg block?
Now we consider there are frictions between the floor and the blocks static friction coefficient u2 is 0.6 and kinetic friction coefficient 0.5
c)Draw the free diagram for 3kg and 5 kg block.
- 天同Lv 76 年前最愛解答
Since a diagram is missing, I assume that the 3 kg block is in front of the 5 kg block. The force of 40N applies onto the 3 kg block.
(a) Acceleration of the blocks = 40/(3+5) m/s^2 = 5 m/s^2
Hence, tension in the string connecting the blocks
= 5 x 5 N = 25 N
(b) 5 m/s^2 from (a)
(c) The block in front (3 kg block) is acted by three forces:
(i) 40N pulling force
(ii) tension in the string (in direction opposite to the 40N force)
(iii) frictional force (in direction opposite to the 40N force)
The 5 kg block is acted by two forces:
(i) string tension
(ii) frictional force (in direction opposite to string tension)