# 高等physics

### 2 個解答

• 天同
Lv 7
7 年前
最愛解答

Angular acceleration a = dw/dt is a differential, you cannot split it up like an algebraic term and combine with delta(w). This is mathematically incorrect.

The correct derivation is as follows:

dW = T.(ds)

where dW is the work done, T is the torque and ds is the angular displacement.

Because T = I.a

where I is the moment of inertia

Thus, dW = I.a.(ds)

but a = dw/dt (w is the angular velocity)

dW = I.(dw/dt).ds

Using the Chain Rule in calculus, dw/dt = (dw/ds).(ds/dt) = w(dw/ds)

Hence, dW = I.w.(dw/ds).ds

dW = I.w.dw

W = integral { I.w.dw} with limits of integration from wi to wf

i.e. W = I.[integral{w.dw}]

W = I.(wf^2 - wi^2)/2 = (1/2)I(wf)^2 - (1/2).I.(wi)^2

2013-10-13 21:14:18 補充：

Without using integration, you could use the method below:

In your equation: W = I.(dw/dt).(dw)

where (dw) denotes "delta w", and (dt) denotes "delta t".

Hence, W = I.(dw).(dw/dt)

2013-10-13 21:19:06 補充：

sorry...a typing mistake in the equation, it should be:

W = I.(dw/dt).(ds)

where (dw) denotes "delta w", and (dt) denotes "delta t" and (ds) denotes "delta theta".

Hence, W = I.(dw).(ds/dt)

2013-10-13 21:25:06 補充：

(cont'd)...

Be aware that (ds/dt) is NOT the instantaneous angular velocity. It is the AVERAGE angular velocity, as it is "delta theta/delta t", not a differential.

2013-10-13 21:28:18 補充：

(cont'd)...

Hence, (ds/dt) = (wi + wf)/2

where wi and wf are the initial and final angular velocities respectively, assuming that the angular acceleration is constant.

Because (dw) = (wf - wi)

Now, W = I.(dw).(ds/dt) = I.(wf - wi).(wi + wf)/2

W = I.(wf^2 - wi^2)/2 = (I/2)(wf)^2 - (I/2).(wi)^2

2013-10-13 21:31:40 補充：

Therefore, what your mistake is that you have mixed up the two "delta w". The fisrt "delta w" is the difference in angular velocities, (wf - wi).

2013-10-13 21:36:42 補充：

The second "delta w", which comes from "(delta theta)/(delta t)", is the average angular velocity, which is (wi + wf)/2. Strictly speaking, it should not be denoted by "delta w", which gives a confusion that it is a "difference in angular velocities".

• 匿名
7 年前

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