數學題目(續三角)一問

請解答下列網址的第一題(Q1):

https://docs.google.com/document/d/1GYPN1AVRrmbpyr...

更新:

答案已知,想知其步驟!

THX

1 個解答

評分
  • 7 年 前
    最佳解答

    Some special angles :

    sin0° = 0, sin90° = 1, sin180° = 0, sin270° = -1

    cos0° = 1, cos90° = 0, cos180° = -1, cos270° = 0

    [sin²90° + cos²90°] / [3sin³270° - cos180°]

    = [(0)² + (1)²] / [3 x (-1)² - (-1)]

    = [0 + 1] / [-3 + 1]

    = -1/2

    資料來源: micatkie
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