F.2 ratio 文字題,help~!!!!!

John shares 100 marbles with Jack in the ratio 1 : 3. Jack then gives 45 of his marbles to Joseph. Find the ratio of John's number of marbles to that of Jack to that of Joseph.

更新:

Mary has 28 $5-coins, some $2-coins and some $0.5-coins. If the ratio of the value of $5-coins to that of $2-coins to that of $0.5-coins is 35 : 24 : 11, find

(a) the number of $ 2-coins Mary has,

(b) the ratio of the number of $5-coins to $2-coins to $0.5-coins

4 個解答

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  • 最愛解答

    John shares 100 marbles with Jack in the ratio 1 : 3.

    so, John has 25 and Jack has 75

    Jack then gives 45 of his marbles to Joseph.

    so, Jack has 30 and Joseph has 45

    the ratio of John's number of marbles to that of Jack to that of Joseph.

    = 25 : 30 : 45

    = 5 : 6 : 9

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    還有的是人家答了大家就不要答!

    加我好友^_^

    2012-01-05 20:06:08 補充:

    well...since someone copied my answers before and finally got the "best answer", i don't know this happen again.

    2012-01-06 18:26:21 補充:

    (a) let Mary has k $2-coins

    28*5 : k*2 = 35 : 24

    140 : 2k = 35 : 24

    70 / k = 70 / 48

    k = 48

    2012-01-06 18:29:54 補充:

    (b) let Mary has n $0.5-coins

    28*5 : 48*2 : n*0.5 = 35 : 24 : 11

    140 : 96 : 0.5n = 140 : 96 : 44

    0.5n = 44

    n = 88

    ratio of the number of $5-coins to $2-coins to $0.5-coins is

    28 : 48 : 88

    = 7 : 12 : 22

    資料來源: I am HKCEE MATH A grade, I am HKCEE MATH A grade, I am HKCEE MATH A grade
  • 9 年前

    Mary has 28 $5-coins, some $2-coins and some $0.5-coins. If the ratio of the value of $5-coins to that of $2-coins to that of $0.5-coins is 35 : 24 : 11, find

    (a) the number of $ 2-coins Mary has,

    let A be the number of $2-coins

    2 x A / (5 x 28 + 2 x A) = 24 / (24 + 35)

    2A x 59 = 24 x (140 + 2A)

    118A = 3360 + 48A

    70A = 3360

    A = 48

    (b) the ratio of the number of $5-coins to $2-coins to $0.5-coins

    Let B be the number of $0.5-coins

    0.5 x B / (5 x 28 + 0.5 x B) = 11 / (11 + 35)

    0.5B x 46 = 11 x (140 + 0.5B)

    23B = 1540 + 5.5B

    17.5B = 1540

    B = 88

    the ratio of the number of $5-coins to $2-coins to $0.5-coins :

    28 : 48 : 88

    = 7 : 12 : 22

  • 9 年前

    人家答了大家就不要答?

    是何道理? 為何你那麼霸道不准人答?

    我都係HKCEE A grade , 年年出幾千個...

  • 原來係搵佢地最終有既波子既比率...

    2012-01-05 20:00:50 補充:

    唔該晒你丫~! :D

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