ping
Lv 5
ping 發問於 科學及數學數學 · 10 年前

Find the particular solution 1

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1 個解答

評分
  • 10 年前
    最愛解答

    (a) I can only tell you how to draw it since I don't have the necessary software. For exapmle, at (1,1) ,dy/dx = -2 and then you draw a small line segment at (1,1) with slope -2 is OK.

    (b) At (1,-1) dy/dx = 2

    So, the equation is y + 1 = 2(x - 1)

    Sub. x = 1.1, y = -0.8

    (c) dy/dx = -2x/y

    -y dy = 2x dx

    -y^2/2 = x^2 + C

    Sub. (1,-1) C = -3/2 and so y = -√(3x - 2)

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