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匿名 發問於 科學及數學數學 · 1 十年 前

SUPER URGENT CALCULUS QUESTIONS!

SUPER URGENT!

1. Find the equation of the line perpendicular to y=3, and which passes through the point (−2, 4)

2. A line passes through the point (a, a^1/2). The slope of the line is 1/2a^−1/2. Give the equation of the line.

3. If the curve y=√(ax) passes through the point (p, q), then the curve y=3√(ax)−2 passes through the point (p, ___ )?

1 個解答

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  • 1 十年 前
    最佳解答

    1. the line perpendicular to y=3 is x=-2

    since the only thing perpendicular to y is x

    and x-coordinate of the point is -2

    2. (y-a^1/2)/(x-a) = 1/2a^−1/2

    (y-a^1/2) = (1/2a^−1/2)(x-a)

    (y-a^1/2) = 1/2 (x-a) a^(−1/2)

    (y-a^1/2) = 1/2a^(−1/2) x-1/2a^(1/2)

    y= 1/2a^(−1/2) x+1/2a^(1/2)

    3. curve y=√(ax) passes through the point (p, q)

    so √(ap) = q

    3√(ap)−2 = 3q-2

    so curve y=3√(ax)−2 passes through the point (p, 3q-2 )

    資料來源: my math knowledge
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