Maths Problems of verify identities of sine,cos,tan

(cosxcotx/1-sinx) -1 = cscx

Please make the process to verity left hand side as right hand side.

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  • 1 十年前
    最愛解答

    LHS

    =[cosxcotx/(1-sinx)] -1

    =(cosx*(cosx/sinx)/(1-sinx)) -1

    =(cos^2x)/sinx(1-sinx)-1

    =[cos^2x-sinx(1-sinx)]/sinx(1-sinx)

    =[cos^2x-sinx+sin^2x)]/sinx(1-sinx)

    =(1-sinx)/sinx(1-sinx)

    =1/sinx

    =cscx

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