Ling 發問於 科學及數學其他 - 科學 · 1 十年前

急問!!Calculation about stress and strain

A 0.505-cm-diameter aluminium(Al) alloy test bar is subjected to a load of 2000N.If the diameter of the bar is 0.490cm under this load, determine (a)the stress and (b)strain under this load.

Assume no volume change of the bar during extension.

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  • 1 十年前
    最愛解答

    a) Stress = Force (N) / Area (cm2)

    = 2000 / 3.14 x 0.505x 0.505

    = 2497.6 N/cm2

    = 24.98 N / mm2

    b) (i)Young modulus =(ii)Stress / (iii) Strain

    (i) Young modulus of (Al) , MUST has been given by the question.

    (ii) Stress = 2000 / 3.14 x 0.49 x 0.49

    = 2652.8 N/cm2

    =26.53 N / mm2

    So, (iii) = 2652.8 N/cm2 / Young modulus pf Al

    2006-12-11 17:58:50 補充:

    Sorry , my mistake about the diameter. Please re-calculate the Area(s) . Area = 3.14 x r2

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