HELP!!! (方程)complete There have two questions
Complete to answer me.............
1)The sum of three numbers A,B and C is 405.A is four times B,and C is greater than A by 45.Find these three numbers.
2)100 buns were distributed to 100 monks.If each elderly monk got 3 buns,and every three young monks had to share 1 bun,how many elderly monks and young monks were three ?
- HunterLv 61 十年前最愛解答
Let x be the no. of elderly monks.
So, the no. of younger monks is (100-x).
100buns were distributed with elderly monks got 3buns per head and 3 young monks had to share 1 bun.
100 = 3x + (100-x)/3 * 1
100 = 3x + (100-x)/3
100*3 = 3x * 3 + (100-x)/3*3
300 = 9x + 100 - x
200 = 8x
So, there are 25 elderly monks and (100-25)=75young monks.
- 1 十年前
2)Let there are a elderly monks and b young monks, x be get the numbers of buns
because every elderly monk can get three buns, so 75/3=25 elderly monks
every three young monks share one bun, so 25*3=75 young monks
hope this can help you to solve your problem資料來源： myself