# physics

The gravity of the moon is only about one-sixth that of the earth&#39;s:

g earth=9.8 ms-2 g moon=1.6 ms-2

a) Try and estimate the maximum height you can reach by jumping on earth. Hence estimate your initial velocity at the moment when your feet leave the ground.

b) Assuming that you can attain the same initial velocity on the moon, estimate the maximum height you can reach if you jup on the moon.

Thank you

### 2 個解答

• 最愛解答

The gravity of the moon is only about one-sixth that of the earth's:

g earth=9.8 ms-2 g moon=1.6 ms-2

a) Try and estimate the maximum height you can reach by jumping on earth. Hence estimate your initial velocity at the moment when your feet leave the ground.

v2 = u2 – 2gEhE

at the maximum height，v = 0，

such that

02 = u2 – 2gEhE

hE = u2 / 2gE ___(1)

where u is initial velocity，gE = gravity of the earth

b) Assuming that you can attain the same initial velocity on the moon, estimate the maximum height you can reach if you jump on the moon.

gM = gravity of the moon，

v2 = u2 – 2gMhM

at the maximum height，v = 0，

such that

02 = u2 – 2gMhM

hM = u2 / 2gM ___(2)

(2) divide by (1)

hE/hM = (u2 / 2gE)/(u2 / 2gM)

hM = hE(gE/gM) = hE(6/1)

hM = 6hE

• The gravity of the moon is only about one-sixth that of the earth&#39;s:

g earth=9.8 ms-2 g moon=1.6 ms-2

a) Try and estimate the maximum height you can reach by jumping on earth. Hence estimate your initial velocity at the moment when your feet leave the ground.

v2 = u2 – 2gEhE

at the maximum height，v = 0，

such that

02 = u2 – 2gEhE

hE = u2 / 2gE ___(1)

where u is initial velocity，gE = gravity of the earth

b) Assuming that you can attain the same initial velocity on the moon, estimate the maximum height you can reach if you jump on the moon.

gM = gravity of the moon，

v2 = u2 – 2gMhM

at the maximum height，v = 0，

such that

02 = u2 – 2gMhM

hM = u2 / 2gM ___(2)

(2) divide by (1)

hE/hM = (u2 / 2gE)/(u2 / 2gM)

hM = hE(gE/gM) = hE(6/1)

hM = 6hE