pigeonhole principle
Twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary arrangement. Show that some three consecutive players have the sum of their numbers at least 20.
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- myisland8132Lv 71 十年前最愛解答
if no three consecutive players have the sum of their numbers at least 20,
then the maximum value is 19
Generally speaking, for a circular arrangement, the total no of count of three consecutive players is 12
the maximum total values is 12*19= 228
however, from the other point of view, in the total combination of three consecutive players, each no [1,2...12] is counted three times
total values =78*3=234
since 228 < 234
it is a contradiction
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